ml=a over $\mathbb {F}_{2^{n}}$

Sihem Mesnager, Kwang Ho Kim, Jong Hyok Choe, Dok Nam Lee, Dae Song Go. ml=a over $\mathbb {F}_{2^{n}}$. Cryptography and Communications, 12(4):809-817, 2020. [doi]

Abstract

Abstract is missing.